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Cleveland takes 1-0 lead in World Series

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Posted at 11:48 PM, Oct 25, 2016
and last updated 2016-10-25 23:50:35-04
Corey Kluber throws a pitch against the Chicago Cubs during Game One of the 2016 World Series. (Photo: Ezra Shaw/Getty Images)

Corey Kluber throws a pitch against the Chicago Cubs during Game One of the 2016 World Series. (Photo: Ezra Shaw/Getty Images)

CLEVELAND, Ohio – Behind a dominant performance from starting pitcher Corey Kluber, the Indians defeated the Cubs, 6-0 in game one of the 2016 World Series. It’s the first shutout in game one of a World Series since 1990, when Cincinnati defeated Oakland, 7-0.

Kluber became the first pitcher in Major League Baseball history to record eight strikeouts in the first three innings of a World Series game. He finished the night allowing four hits, no runs, with nine strikeouts in six innings. He’s the first pitcher since 1966, just the sixth overall, to toss at least six scoreless innings with at least 9 strikeouts in his first World Series start.

Cleveland scored a pair of runs in the first inning, then tacked-on one more in the fourth on Roberto Perez’s solo home run. Perez again homered, a three-run shot, in the eighth inning.

The team that is victorious in game one of the World Series has gone on to win the series 12 of the past 13 years. Game two of the best of seven series is Wednesday in Cleveland.